In this example you'll learn the application of current divider principle to a circuit whose equivalent resistance and one of the two resistors are known.

Statement: A current divider circuit has two resistors with R1 = 30 ohms and R2 is unknown. While the equivalent resistance is 20 ohms. The current flowing through R2 is 2 mA.

Statement: A current divider circuit has two resistors with R1 = 30 ohms and R2 is unknown. While the equivalent resistance is 20 ohms. The current flowing through R2 is 2 mA.

By appliying current divider theorem to I1, we obtain.

I

_{1}= (20 ohm/ 30 ohm) * I_{t}
or I

_{1}= 0.666 I_{t}
From Kirchhoff's Current Law:

I

_{t}= I_{1}+ I_{2}
or

I

_{t}= 0.66 I_{t}+ I_{2}
0.33 I

0.33 I

or I

Putting value of I

I

_{t}= I_{2}/0.33 I

_{t }= 2 mAor I

_{t }= 6 mAPutting value of I

_{t }in I_{1}.I

_{1 }= 3.99 mA