Learn everything about Current Division in Parallel Circuits.

Current Divider Rule Example # 6: 10 mA Current Enters node

Statement: 10 mA current enters the node formed by two parallel resistors having their resistances 20 Ω and 2 Ω. Find the divided current by applying the current divider rule.
current-divider-rule-example-6
Solution: We know the general formula for any divider circuit is:

And in case of two resistors:
case-of-two-resistors
In our present case, It is 10 mA. Whereas the Rt can be calculated by the formula:

The equivalent resistance is:
Rt =
R1 * R2 / R1 + R2

Rt = =
2 * 20 / 2 + 20

Rt = 1.81 Ω
In our case for two resistors:
The current across first resistor: I1 =
1.81 Ω / 20 Ω
* 10 mA = 0.905 mA
and across the second resistor: I2 =
1.81 Ω / 2 Ω
* 10 mA = 9.05 mA
You can also verify the results from current divider rule calculator.