Statement: Two resistors of 8.6 ohms and 32 ohms are connected in a parallel configuration. The input source is 800 mA. Apply the current divider principle to find the current through both resistors.

Solution: Consider the circuit diagram:

In the present case the overall current (It = 800 mA)

From the formula:

R

The equivalent resistance is R

I

= [6.78 Ω / 8.6 Ω ] * 800 mA

= 630 mA

I

= [6.78 Ω / 32 Ω ] * 800 mA

= 169.5 mA

Solution: Consider the circuit diagram:

In the present case the overall current (It = 800 mA)

From the formula:

R

_{1}= 8.6 Ω; R_{2}= 32 ΩThe equivalent resistance is R

_{t}= 6.77 ΩI

_{1}= [R_{t }/ R_{1}] * I_{t}.= [6.78 Ω / 8.6 Ω ] * 800 mA

= 630 mA

I

_{2}= [R_{t }/ R_{2}] * I_{t}.= [6.78 Ω / 32 Ω ] * 800 mA

= 169.5 mA