Statement: Two resistors of 8.6 ohms and 32 ohms are connected in a parallel configuration. The input source is 800 mA. Apply the current divider principle to find the current through both resistors.
Solution: Consider the circuit diagram:
In the present case the overall current (It = 800 mA)
From the formula:
R1 = 8.6 Ω; R2 = 32 Ω
The equivalent resistance is Rt = 6.77 Ω
I1= [Rt / R1] * It.
= [6.78 Ω / 8.6 Ω ] * 800 mA
= 630 mA
I2= [Rt / R2] * It.
= [6.78 Ω / 32 Ω ] * 800 mA
= 169.5 mA
Solution: Consider the circuit diagram:
In the present case the overall current (It = 800 mA)
From the formula:
R1 = 8.6 Ω; R2 = 32 Ω
The equivalent resistance is Rt = 6.77 Ω
I1= [Rt / R1] * It.
= [6.78 Ω / 8.6 Ω ] * 800 mA
= 630 mA
I2= [Rt / R2] * It.
= [6.78 Ω / 32 Ω ] * 800 mA
= 169.5 mA